44x^2+23x=0

Solution for 44x^2+23x=0 equation:

44x^2+23x=0

a = 44; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·44·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*44}=\frac{-46}{88}
=-23/44
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*44}=\frac{0}{88}
=0
$